Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:43Z

∇²t = 0

∇ × E = −∂B/∂t

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

det| 6 4 ; 3 7 | = 30

8ψ² + 7ψ + 0 = 0

186K

det| 11 5 ; 0 12 | = 132

411K

ΔS ≥ 0

6x² + 6x + 1 = 0

448K

det| 5 6 ; 2 6 | = 18

22K

1z² + 3z + 2 = 0

8θ² + 8θ + 6 = 0

459K

d/dt [t^3] = 3t^2

406K

7t² + 3t + 1 = 0

ω = 2πf

181K

det| 11 5 ; 2 12 | = 122

det| 8 3 ; 4 9 | = 60