Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 22:36Z

N₂ + 3H₂ ⇌ 2NH₃

∑_{k=1}^{n} k = n(n+1)/2

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∑_{k=1}^{n} k = n(n+1)/2

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9ψ² + 4ψ + 2 = 0

N₂ + 3H₂ ⇌ 2NH₃

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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d/dβ [β^6] = 6β^5

det| 7 4 ; 4 8 | = 40

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det| 11 5 ; 0 12 | = 132

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4t² + 3t + 3 = 0

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det| 5 2 ; 3 6 | = 24

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det| 9 8 ; 3 10 | = 66

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∇²z = 0

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det| 2 8 ; 7 3 | = -50

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