Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 12:06Z
∑_{k=1}^{n} k = n(n+1)/2
Fe₂O₃ + 3CO → 2Fe + 3CO₂
460K
4y² + 7y + 7 = 0
det| 4 8 ; 3 5 | = -4
411K
∇²t = 0
6β² + 2β + 2 = 0
2φ² + 2φ + 5 = 0
det| 9 4 ; 7 10 | = 62
181K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
80K