Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-19 16:17Z
∂ψ/∂φ = 6ψ
∑_{k=1}^{n} k = n(n+1)/2
451K
11ψ² + 2ψ + 6 = 0
\frac{2}{2} \sum_{i=1}^{n} i^{2}
252K
λ = h/p
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
48K
det| 9 4 ; 1 10 | = 86
411K
\frac{9}{7} \sum_{i=1}^{n} i^{2}
\frac{2}{8} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
401K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
420K
\frac{10}{3} \sum_{i=1}^{n} i^{2}