Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:02Z

10y² + 2y + 6 = 0

e^{i\pi} + 1 = 0

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-t²) dt = √π / 2

11t² + 9t + 7 = 0

186K

d/dt [t^3] = 3t^2

411K

e^{i\pi} + 1 = 0

det| 12 2 ; 2 13 | = 152

448K

11t² + 9t + 5 = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

e^{i\pi} + 1 = 0

459K

\lim_{β\to 0} \frac{\sin β}{β} = 1

406K

∇ × E = −∂B/∂t

181K

e^{i\pi} + 1 = 0

80K

8ψ² + 7ψ + 0 = 0

359K