Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 21:38Z
10y² + 2y + 6 = 0
∫₀^∞ e^(-θ²) dθ = √π / 2
438K
∫₀^∞ e^(-t²) dt = √π / 2
det| 11 4 ; 5 12 | = 112
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∫₀^∞ e^(-α²) dα = √π / 2
411K
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 7 4 ; 4 8 | = 40
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