Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 06:07Z

∑_{k=1}^{n} k = n(n+1)/2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

273K

6n² + 7n + 6 = 0

263K

e^{i\pi} + 1 = 0

∫₀^∞ e^(-ω²) dω = √π / 2

139K

∇²z = 0

108K

2H₂ + O₂ → 2H₂O

∑_{k=1}^{n} k = n(n+1)/2

333K

det| 7 4 ; 4 8 | = 40

160K

det| 4 8 ; 0 5 | = 20

∇ × E = −∂B/∂t

439K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

413K

det| 4 7 ; 7 5 | = -29

10t² + 9t + 5 = 0

297K

CH₄ + 2O₂ → CO₂ + 2H₂O

128K

N₂ + 3H₂ ⇌ 2NH₃

404K