Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 16:35Z

10γ² + 4γ + 3 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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d/dβ [β^11] = 11β^10

iħ ∂ψ/∂t = Ĥψ

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12y² + 5y + 7 = 0

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3x² + 4x + 6 = 0

det| 7 4 ; 4 8 | = 40

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λ = h/p

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∑_{k=1}^{n} k = n(n+1)/2

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\frac{4}{6} \sum_{i=1}^{n} i^{2}

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∂α/∂ω = 3α

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N₂ + 3H₂ ⇌ 2NH₃

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PV = nRT

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