Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:34Z

∇²t = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

det| 6 4 ; 3 7 | = 30

∇²n = 0

186K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

411K

ΔS ≥ 0

det| 7 6 ; 1 8 | = 50

448K

CH₄ + 2O₂ → CO₂ + 2H₂O

22K

1z² + 3z + 2 = 0

e^{i\pi} + 1 = 0

459K

N₂ + 3H₂ ⇌ 2NH₃

406K

7t² + 3t + 1 = 0

Fe₂O₃ + 3CO → 2Fe + 3CO₂

181K

det| 7 4 ; 4 8 | = 40

80K

det| 8 3 ; 4 9 | = 60

∑_{k=1}^{n} k = n(n+1)/2

359K

10γ² + 8γ + 2 = 0

∇ × E = −∂B/∂t

λ = h/p