Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:37Z

∇²n = 0

N₂ + 3H₂ ⇌ 2NH₃

273K

F = ma

263K

9r² + 4r + 1 = 0

PV = nRT

139K

det| 7 4 ; 4 8 | = 40

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

PV = nRT

333K

E = mc²

160K

11γ² + 3γ + 6 = 0

∇ × E = −∂B/∂t

439K

F = G m₁m₂ / r²

413K

\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1

11z² + 3z + 4 = 0

297K

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

128K

det| 6 1 ; 3 7 | = 39

Fe₂O₃ + 3CO → 2Fe + 3CO₂

404K

e^{i\pi} + 1 = 0

N₂ + 3H₂ ⇌ 2NH₃

∑_{k=1}^{n} k = n(n+1)/2