Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 16:21Z

10γ² + 4γ + 3 = 0

det| 5 9 ; 7 6 | = -33

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

d/dβ [β^11] = 11β^10

N₂ + 3H₂ ⇌ 2NH₃

186K

3z² + 5z + 1 = 0

411K

3x² + 4x + 6 = 0

det| 7 4 ; 4 8 | = 40

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

22K

4t² + 3t + 3 = 0

459K

∑_{k=1}^{n} k = n(n+1)/2

406K

det| 10 2 ; 3 11 | = 104

181K

det| 4 7 ; 2 5 | = 6

80K

2n² + 4n + 0 = 0

359K