Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 10:08Z

∇²t = 0

e^{i\pi} + 1 = 0

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

\frac{8}{3} \sum_{i=1}^{n} i^{2}

∇ × E = −∂B/∂t

186K

∑_{k=1}^{n} k = n(n+1)/2

411K

CaCO₃ → CaO + CO₂

∇²r = 0

448K

det| 7 4 ; 4 8 | = 40

22K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

N₂ + 3H₂ ⇌ 2NH₃

459K

∂ψ/∂β = 3ψ

406K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

181K

∂y/∂γ = 8y

80K