Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:59Z

11n² + 5n + 4 = 0

CH₄ + 2O₂ → CO₂ + 2H₂O

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

∫₀^∞ e^(-x²) dx = √π / 2

det| 7 2 ; 7 8 | = 42

186K

det| 2 6 ; 0 3 | = 6

411K

4φ² + 6φ + 2 = 0

6t² + 6t + 4 = 0

448K

det| 7 4 ; 4 8 | = 40

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

N₂ + 3H₂ ⇌ 2NH₃

459K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

406K

∇²ω = 0

CH₄ + 2O₂ → CO₂ + 2H₂O

181K

∫₀^∞ e^(-ψ²) dψ = √π / 2

80K

N₂ + 3H₂ ⇌ 2NH₃

359K

det| 3 6 ; 0 4 | = 12

455K