Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:05Z

10y² + 2y + 6 = 0

∂n/∂θ = 3n

460K

∇ × E = −∂B/∂t

438K

∫₀^∞ e^(-t²) dt = √π / 2

10γ² + 8γ + 7 = 0

186K

\lim_{β\to 0} \frac{\sin β}{β} = 1

411K

e^{i\pi} + 1 = 0

∂ψ/∂β = 3ψ

448K

det| 10 7 ; 3 11 | = 89

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

\lim_{t\to 0} \frac{\sin t}{t} = 1

459K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

406K

d/dt [t^3] = 3t^2

181K

ΔS ≥ 0

80K

det| 5 9 ; 7 6 | = -33

359K

8ψ² + 7ψ + 0 = 0

455K