Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:21Z

11n² + 5n + 4 = 0

det| 7 4 ; 4 8 | = 40

460K

N₂ + 3H₂ ⇌ 2NH₃

438K

∫₀^∞ e^(-x²) dx = √π / 2

∑_{k=1}^{n} k = n(n+1)/2

186K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

411K

4φ² + 6φ + 2 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

448K

det| 5 9 ; 7 6 | = -33

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

6x² + 6x + 1 = 0

459K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

406K

∇²ω = 0

∑_{k=1}^{n} k = n(n+1)/2

181K

d/dα [α^3] = 3α^2

d/dr [r^2] = 2r^1

ΔS ≥ 0