Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:34Z

∇²t = 0

det| 5 6 ; 2 6 | = 18

460K

∇ × E = −∂B/∂t

438K

det| 6 4 ; 3 7 | = 30

2H₂ + O₂ → 2H₂O

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det| 12 1 ; 5 13 | = 151

411K

ΔS ≥ 0

d/dt [t^3] = 3t^2

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

22K

1z² + 3z + 2 = 0

\oint_C \vec{F}\cdot d\vec{r} = 0

459K

8ψ² + 7ψ + 0 = 0

406K

\oint_C \vec{F}\cdot d\vec{r} = 0

181K

8θ² + 8θ + 6 = 0

80K