Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:57Z

10y² + 2y + 6 = 0

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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\lim_{β\to 0} \frac{\sin β}{β} = 1

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∫₀^∞ e^(-t²) dt = √π / 2

ΔS ≥ 0

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8ψ² + 7ψ + 0 = 0

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e^{i\pi} + 1 = 0

iħ ∂ψ/∂t = Ĥψ

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∂ψ/∂β = 3ψ

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

N₂ + 3H₂ ⇌ 2NH₃

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N₂ + 3H₂ ⇌ 2NH₃

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6r² + 3r + 1 = 0

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det| 2 8 ; 7 3 | = -50

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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