Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 16:50Z
10γ² + 4γ + 3 = 0
∑_{k=1}^{n} k = n(n+1)/2
460K
CH₄ + 2O₂ → CO₂ + 2H₂O
438K
d/dβ [β^11] = 11β^10
3x² + 4x + 6 = 0
det| 9 4 ; 1 10 | = 86
22K
CH₄ + 2O₂ → CO₂ + 2H₂O
459K
∑_{k=1}^{n} k = n(n+1)/2
406K
∑_{k=1}^{n} k = n(n+1)/2
181K