Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:45Z

3γ² + 8γ + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

N₂ + 3H₂ ⇌ 2NH₃

438K

PV = nRT

det| 11 5 ; 0 12 | = 132

186K

11t² + 9t + 5 = 0

411K

det| 1 9 ; 5 2 | = -43

det| 7 4 ; 4 8 | = 40

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

22K

ω = 2πf

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

459K

∑_{k=1}^{n} k = n(n+1)/2

406K

5z² + 8z + 3 = 0

181K

8θ² + 8θ + 6 = 0

80K