Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:47Z

∇²n = 0

10β² + 4β + 1 = 0

273K

∑_{k=1}^{n} k = n(n+1)/2

263K

9r² + 4r + 1 = 0

10ω² + 7ω + 4 = 0

139K

∂n/∂θ = 3n

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

∑_{k=1}^{n} k = n(n+1)/2

333K

det| 4 8 ; 3 5 | = -4

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11γ² + 3γ + 6 = 0

N₂ + 3H₂ ⇌ 2NH₃

439K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

413K

6r² + 3r + 1 = 0

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det| 7 8 ; 4 8 | = 24

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det| 7 4 ; 4 8 | = 40

404K

10ψ² + 5ψ + 0 = 0

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