Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:39Z

11n² + 5n + 4 = 0

E = mc²

460K

det| 7 4 ; 4 8 | = 40

438K

∫₀^∞ e^(-x²) dx = √π / 2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

186K

e^{i\pi} + 1 = 0

411K

4φ² + 6φ + 2 = 0

12γ² + 9γ + 1 = 0

448K

F = G m₁m₂ / r²

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

\oint_C \vec{F}\cdot d\vec{r} = 0

459K

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

406K

∇²ω = 0

∂β/∂β = 6β

181K

∫₀^∞ e^(-t²) dt = √π / 2

80K

d/dr [r^2] = 2r^1

∇ × E = −∂B/∂t

359K

iħ ∂ψ/∂t = Ĥψ

455K