Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-17 22:39Z
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
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∑_{k=1}^{n} k = n(n+1)/2
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9ψ² + 4ψ + 2 = 0
d/dβ [β^6] = 6β^5
det| 9 4 ; 1 10 | = 86
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∫₀^∞ e^(-θ²) dθ = √π / 2
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det| 6 1 ; 4 7 | = 38
\frac{6}{5} \sum_{i=1}^{n} i^{2}
5ψ² + 8ψ + 3 = 0