Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 22:39Z

N₂ + 3H₂ ⇌ 2NH₃

10t² + 9t + 5 = 0

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det| 9 4 ; 1 10 | = 86

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9ψ² + 4ψ + 2 = 0

11t² + 9t + 7 = 0

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\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

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d/dβ [β^6] = 6β^5

iħ ∂ψ/∂t = Ĥψ

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e^{i\pi} + 1 = 0

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det| 6 1 ; 4 7 | = 38

\lim_{t\to 0} \frac{\sin t}{t} = 1

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\lim_{t\to 0} \frac{\sin t}{t} = 1

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iħ ∂ψ/∂t = Ĥψ

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∑_{k=1}^{n} k = n(n+1)/2

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F = G m₁m₂ / r²

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