Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 03:04Z

∇²x = 0

4t² + 3t + 3 = 0

451K

10ψ² + 5ψ + 0 = 0

264K

det| 3 9 ; 1 4 | = 3

E = mc²

297K

8ψ² + 7ψ + 0 = 0

252K

CaCO₃ → CaO + CO₂

\frac{4}{6} \sum_{i=1}^{n} i^{2}

48K

∇ × E = −∂B/∂t

411K

det| 8 9 ; 4 9 | = 36

∑_{k=1}^{n} k = n(n+1)/2

377K

CaCO₃ → CaO + CO₂

299K

det| 7 6 ; 6 8 | = 20

∇²t = 0

401K

N₂ + 3H₂ ⇌ 2NH₃

420K

\oint_C \vec{F}\cdot d\vec{r} = 0

∫₀^∞ e^(-θ²) dθ = √π / 2

109K

d/dt [t^3] = 3t^2

184K