Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 04:47Z
∇²n = 0
det| 11 5 ; 0 12 | = 132
263K
9r² + 4r + 1 = 0
det| 1 4 ; 3 2 | = -10
108K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
11γ² + 3γ + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
439K
\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1