Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:05Z

10y² + 2y + 6 = 0

N₂ + 3H₂ ⇌ 2NH₃

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det| 3 6 ; 0 4 | = 12

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∫₀^∞ e^(-t²) dt = √π / 2

e^{i\pi} + 1 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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e^{i\pi} + 1 = 0

\frac{8}{7} \sum_{i=1}^{n} i^{2}

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∑_{k=1}^{n} k = n(n+1)/2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

det| 7 4 ; 4 8 | = 40

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ΔS ≥ 0

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λ = h/p

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∑_{k=1}^{n} k = n(n+1)/2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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det| 9 8 ; 3 10 | = 66

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