Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-19 18:26Z
e^{i\pi} + 1 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
451K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
264K
λ = h/p
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
252K
det| 6 7 ; 7 7 | = -7
\frac{12}{6} \sum_{i=1}^{n} i^{2}
411K
∇²ψ = 0
∂γ/∂γ = 9γ
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
E = mc²