Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 16:35Z
10γ² + 4γ + 3 = 0
∑_{k=1}^{n} k = n(n+1)/2
460K
d/dβ [β^11] = 11β^10
det| 7 4 ; 4 8 | = 40
186K
3x² + 4x + 6 = 0
det| 4 2 ; 6 5 | = 8
448K
det| 7 6 ; 1 8 | = 50
459K
∑_{k=1}^{n} k = n(n+1)/2
406K