Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 04:09Z
∇²n = 0
det| 4 8 ; 3 5 | = -4
273K
9r² + 4r + 1 = 0
∫₀^∞ e^(-ω²) dω = √π / 2
139K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
11γ² + 3γ + 6 = 0
det| 5 9 ; 7 6 | = -33
439K
\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1
det| 2 3 ; 5 3 | = -9
297K
det| 10 2 ; 3 11 | = 104
128K