Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 23:02Z

11t² + 8t + 0 = 0

11φ² + 4φ + 0 = 0

460K

N₂ + 3H₂ ⇌ 2NH₃

438K

∂ω/∂β = 7ω

∂n/∂θ = 3n

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det| 7 4 ; 4 8 | = 40

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det| 3 3 ; 7 4 | = -9

∑_{k=1}^{n} k = n(n+1)/2

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\frac{4}{9} \sum_{i=1}^{n} i^{2}

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PV = nRT

6t² + 6t + 4 = 0

459K

det| 10 7 ; 3 11 | = 89

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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N₂ + 3H₂ ⇌ 2NH₃

80K