Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 15:34Z
11n² + 5n + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
460K
∫₀^∞ e^(-x²) dx = √π / 2
∑_{k=1}^{n} k = n(n+1)/2
186K
CH₄ + 2O₂ → CO₂ + 2H₂O
411K
4φ² + 6φ + 2 = 0
det| 7 4 ; 4 8 | = 40
22K
∑_{k=1}^{n} k = n(n+1)/2
406K