Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 23:04Z
11t² + 8t + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
460K
∂ω/∂β = 7ω
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
411K
det| 3 3 ; 7 4 | = -9
det| 9 4 ; 1 10 | = 86
22K
det| 7 6 ; 1 8 | = 50
459K
∑_{k=1}^{n} k = n(n+1)/2
406K
∫₀^∞ e^(-x²) dx = √π / 2
181K