Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 16:46Z

10γ² + 4γ + 3 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

\frac{8}{7} \sum_{i=1}^{n} i^{2}

438K

d/dβ [β^11] = 11β^10

det| 7 4 ; 4 8 | = 40

186K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

411K

3x² + 4x + 6 = 0

F = G m₁m₂ / r²

448K

N₂ + 3H₂ ⇌ 2NH₃

22K

det| 9 5 ; 1 10 | = 85

459K

∑_{k=1}^{n} k = n(n+1)/2

406K

6ω² + 4ω + 4 = 0

181K