Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 17:15Z

PV = nRT

6t² + 6t + 4 = 0

451K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

264K

8t² + 4t + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

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CH₄ + 2O₂ → CO₂ + 2H₂O

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F = ma

N₂ + 3H₂ ⇌ 2NH₃

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\frac{12}{6} \sum_{i=1}^{n} i^{2}

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det| 7 6 ; 2 8 | = 44

∑_{k=1}^{n} k = n(n+1)/2

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det| 3 6 ; 0 4 | = 12

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2γ² + 2γ + 6 = 0

det| 7 4 ; 4 8 | = 40

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4n² + 6n + 2 = 0

4φ² + 3φ + 1 = 0