Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-17 22:39Z
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
246K
det| 7 4 ; 4 8 | = 40
118K
9ψ² + 4ψ + 2 = 0
det| 1 4 ; 3 2 | = -10
43K
det| 9 8 ; 3 10 | = 66
261K
d/dβ [β^6] = 6β^5
det| 2 8 ; 7 3 | = -50
424K
det| 6 1 ; 4 7 | = 38
\frac{6}{5} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
447K
∑_{k=1}^{n} k = n(n+1)/2
297K
11y² + 2y + 6 = 0