Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 20:25Z
det| 6 5 ; 4 7 | = 22
det| 11 5 ; 0 12 | = 132
438K
∇²φ = 0
∫₀^∞ e^(-t²) dt = √π / 2
411K
\frac{9}{2} \sum_{i=1}^{n} i^{2}
∫₀^∞ e^(-θ²) dθ = √π / 2
22K
F = ma
ΔS ≥ 0
det| 12 2 ; 2 13 | = 152
181K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∇²γ = 0