Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 13:37Z

F = ma

∑_{k=1}^{n} k = n(n+1)/2

273K

F = G m₁m₂ / r²

263K

\lim_{β\to 0} \frac{\sin β}{β} = 1

∑_{k=1}^{n} k = n(n+1)/2

139K

iħ ∂ψ/∂t = Ĥψ

108K

N₂ + 3H₂ ⇌ 2NH₃

∇ × E = −∂B/∂t

333K

6t² + 6t + 4 = 0

160K

e^{i\pi} + 1 = 0

N₂ + 3H₂ ⇌ 2NH₃

439K

∫₀^∞ e^(-t²) dt = √π / 2

413K

1r² + 8r + 1 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

297K

det| 7 4 ; 4 8 | = 40

128K

e^{i\pi} + 1 = 0

7θ² + 7θ + 2 = 0

iħ ∂ψ/∂t = Ĥψ

∇ × E = −∂B/∂t