Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:24Z

∑_{k=1}^{n} k = n(n+1)/2

10ω² + 7ω + 4 = 0

451K

det| 1 4 ; 3 2 | = -10

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det| 8 9 ; 3 9 | = 45

9ψ² + 7ψ + 3 = 0

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d/dt [t^3] = 3t^2

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

∑_{k=1}^{n} k = n(n+1)/2

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\frac{4}{9} \sum_{i=1}^{n} i^{2}

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det| 2 3 ; 3 3 | = -3

e^{i\pi} + 1 = 0

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det| 3 1 ; 7 4 | = 5

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∑_{k=1}^{n} k = n(n+1)/2

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det| 9 4 ; 1 10 | = 86

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