Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 04:48Z
∇²n = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
273K
9r² + 4r + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
333K
11γ² + 3γ + 6 = 0
\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1
∫₀^∞ e^(-ψ²) dψ = √π / 2
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