Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 02:50Z

det| 5 4 ; 6 6 | = 6

∫₀^∞ e^(-θ²) dθ = √π / 2

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N₂ + 3H₂ ⇌ 2NH₃

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∇²φ = 0

6t² + 6t + 4 = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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det| 12 5 ; 4 13 | = 136

det| 7 4 ; 4 8 | = 40

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∑_{k=1}^{n} k = n(n+1)/2

det| 4 2 ; 6 5 | = 8

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∑_{k=1}^{n} k = n(n+1)/2

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iħ ∂ψ/∂t = Ĥψ

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e^{i\pi} + 1 = 0

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