Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 02:51Z
det| 5 4 ; 6 6 | = 6
∑_{k=1}^{n} k = n(n+1)/2
460K
∇²φ = 0
det| 7 4 ; 4 8 | = 40
186K
∫₀^∞ e^(-t²) dt = √π / 2
411K
det| 12 5 ; 4 13 | = 136
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
448K
∑_{k=1}^{n} k = n(n+1)/2
22K
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
181K