Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 20:35Z

det| 6 5 ; 4 7 | = 22

iħ ∂ψ/∂t = Ĥψ

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

438K

∇²φ = 0

N₂ + 3H₂ ⇌ 2NH₃

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6t² + 6t + 4 = 0

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\frac{9}{2} \sum_{i=1}^{n} i^{2}

∫₀^∞ e^(-θ²) dθ = √π / 2

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iħ ∂ψ/∂t = Ĥψ

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F = ma

∂x/∂ψ = 6x

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det| 3 7 ; 2 4 | = -2

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ΔS ≥ 0

N₂ + 3H₂ ⇌ 2NH₃

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8ψ² + 7ψ + 0 = 0

80K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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