Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 20:38Z

det| 6 5 ; 4 7 | = 22

∑_{k=1}^{n} k = n(n+1)/2

460K

∇ × E = −∂B/∂t

438K

∇²φ = 0

Fe₂O₃ + 3CO → 2Fe + 3CO₂

186K

∇²θ = 0

411K

\frac{9}{2} \sum_{i=1}^{n} i^{2}

8ψ² + 7ψ + 0 = 0

448K

d/dt [t^3] = 3t^2

22K

F = ma

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

459K

∑_{k=1}^{n} k = n(n+1)/2

406K

ΔS ≥ 0

AgNO₃ + NaCl → AgCl↓ + NaNO₃