Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 01:05Z

12γ² + 2γ + 2 = 0

8ψ² + 7ψ + 0 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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∑_{k=1}^{n} k = n(n+1)/2

d/dt [t^3] = 3t^2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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5φ² + 3φ + 0 = 0

∑_{k=1}^{n} k = n(n+1)/2

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∇ × E = −∂B/∂t

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∫₀^∞ e^(-θ²) dθ = √π / 2

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∑_{k=1}^{n} k = n(n+1)/2

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5z² + 8z + 3 = 0

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