Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 22:09Z

3n² + 7n + 7 = 0

∇²β = 0

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-ω²) dω = √π / 2

d/dx [x^3] = 3x^2

186K

d/dt [t^3] = 3t^2

411K

\frac{10}{6} \sum_{i=1}^{n} i^{2}

\binom{n}{k} = \frac{n!}{k!(n-k)!}

448K

∇²t = 0

22K

d/dr [r^12] = 12r^11

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

459K

det| 1 4 ; 3 2 | = -10

406K

∇ × E = −∂B/∂t

181K

E = mc²

80K

8ψ² + 7ψ + 0 = 0

359K