Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-21 09:59Z

∫₀^∞ e^(-z²) dz = √π / 2

det| 7 4 ; 4 8 | = 40

195K

N₂ + 3H₂ ⇌ 2NH₃

262K

10ω² + 8ω + 0 = 0

\lim_{t\to 0} \frac{\sin t}{t} = 1

∫₀^∞ e^(-θ²) dθ = √π / 2

244K

2H₂ + O₂ → 2H₂O

E = mc²

231K

8x² + 2x + 7 = 0

26K

9r² + 6r + 7 = 0

∂y/∂n = 5y

209K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

331K

12θ² + 8θ + 7 = 0

∑_{k=1}^{n} k = n(n+1)/2

163K

10r² + 5r + 3 = 0

12γ² + 9γ + 7 = 0

5φ² + 3φ + 2 = 0