Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:04Z

10y² + 2y + 6 = 0

PV = nRT

460K

det| 7 6 ; 1 8 | = 50

438K

∫₀^∞ e^(-t²) dt = √π / 2

det| 7 4 ; 4 8 | = 40

186K

∑_{k=1}^{n} k = n(n+1)/2

411K

e^{i\pi} + 1 = 0

∇²θ = 0

448K

\lim_{t\to 0} \frac{\sin t}{t} = 1

22K

PV = nRT

459K

N₂ + 3H₂ ⇌ 2NH₃

406K

e^{i\pi} + 1 = 0

181K

∫₀^∞ e^(-t²) dt = √π / 2

80K

∑_{k=1}^{n} k = n(n+1)/2

359K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

455K