Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 18:00Z

e^{i\pi} + 1 = 0

∑_{k=1}^{n} k = n(n+1)/2

451K

N₂ + 3H₂ ⇌ 2NH₃

264K

λ = h/p

\binom{n}{k} = \frac{n!}{k!(n-k)!}

297K

∑_{k=1}^{n} k = n(n+1)/2

252K

det| 6 7 ; 7 7 | = -7

iħ ∂ψ/∂t = Ĥψ

48K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

411K

∇²ψ = 0

d/dx [x^3] = 3x^2

377K

8ψ² + 7ψ + 0 = 0

299K

9α² + 7α + 5 = 0

401K

∑_{k=1}^{n} k = n(n+1)/2

420K