Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:33Z

3γ² + 8γ + 4 = 0

\lim_{r\to 0} \frac{\sin r}{r} = 1

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∑_{k=1}^{n} k = n(n+1)/2

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PV = nRT

d/dt [t^3] = 3t^2

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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det| 1 9 ; 5 2 | = -43

PV = nRT

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det| 9 4 ; 1 10 | = 86

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6r² + 3r + 1 = 0

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\lim_{β\to 0} \frac{\sin β}{β} = 1

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