Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 23:02Z

11t² + 8t + 0 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

∇ × E = −∂B/∂t

438K

∂ω/∂β = 7ω

\lim_{t\to 0} \frac{\sin t}{t} = 1

186K

E = mc²

411K

det| 3 3 ; 7 4 | = -9

det| 7 4 ; 4 8 | = 40

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

22K

PV = nRT

∇²z = 0

459K

F = G m₁m₂ / r²

406K

9α² + 7α + 5 = 0

181K

∫₀^∞ e^(-t²) dt = √π / 2

80K